সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=5$$ এবং সাধারণ অনুপাত: $$r=1991.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=5$$

$$a_2=a_1·r^{n-1}=5\cdot {1991.6}^{2-1}=5\cdot {1991.6}^1=5\cdot 1991.6=9958$$

$$a_3=a_1·r^{n-1}=5\cdot {1991.6}^{3-1}=5\cdot {1991.6}^2=5\cdot 3966470.5599999996=19832352.799999997$$

$$a_4=a_1·r^{n-1}=5\cdot {1991.6}^{4-1}=5\cdot {1991.6}^3=5\cdot 7899622767.295999=39498113836.479996$$

$$a_5=a_1·r^{n-1}=5\cdot {1991.6}^{5-1}=5\cdot {1991.6}^4=5\cdot 15732888703346.71=78664443516733.56$$

$$a_6=a_1·r^{n-1}=5\cdot {1991.6}^{6-1}=5\cdot {1991.6}^5=5\cdot 31333621141585308=1.5666810570792653E+17$$

$$a_7=a_1·r^{n-1}=5\cdot {1991.6}^{7-1}=5\cdot {1991.6}^6=5\cdot 6.24040398655813E+19=3.1202019932790646E+20$$

$$a_8=a_1·r^{n-1}=5\cdot {1991.6}^{8-1}=5\cdot {1991.6}^7=5\cdot 1.242838857962917E+23=6.214194289814584E+23$$

$$a_9=a_1·r^{n-1}=5\cdot {1991.6}^{9-1}=5\cdot {1991.6}^8=5\cdot 2.4752378695189455E+26=1.2376189347594727E+27$$

$$a_{10}=a_1·r^{n-1}=5\cdot {1991.6}^{10-1}=5\cdot {1991.6}^9=5\cdot 4.929683740933931E+29=2.4648418704669656E+30$$