সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=4$$ এবং সাধারণ অনুপাত: $$r=1363.75$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=4$$

$$a_2=a_1·r^{n-1}=4\cdot {1363.75}^{2-1}=4\cdot {1363.75}^1=4\cdot 1363.75=5455$$

$$a_3=a_1·r^{n-1}=4\cdot {1363.75}^{3-1}=4\cdot {1363.75}^2=4\cdot 1859814.0625=7439256.25$$

$$a_4=a_1·r^{n-1}=4\cdot {1363.75}^{4-1}=4\cdot {1363.75}^3=4\cdot 2536321427.734375=10145285710.9375$$

$$a_5=a_1·r^{n-1}=4\cdot {1363.75}^{5-1}=4\cdot {1363.75}^4=4\cdot 3458908347072.754=13835633388291.016$$

$$a_6=a_1·r^{n-1}=4\cdot {1363.75}^{6-1}=4\cdot {1363.75}^5=4\cdot 4717086258320468=18868345033281870$$

$$a_7=a_1·r^{n-1}=4\cdot {1363.75}^{7-1}=4\cdot {1363.75}^6=4\cdot 6.432926384784539E+18=2.5731705539138154E+19$$

$$a_8=a_1·r^{n-1}=4\cdot {1363.75}^{8-1}=4\cdot {1363.75}^7=4\cdot 8.772903357249915E+21=3.509161342899966E+22$$

$$a_9=a_1·r^{n-1}=4\cdot {1363.75}^{9-1}=4\cdot {1363.75}^8=4\cdot 1.196404695344957E+25=4.785618781379828E+25$$

$$a_{10}=a_1·r^{n-1}=4\cdot {1363.75}^{10-1}=4\cdot {1363.75}^9=4\cdot 1.6315969032766851E+28=6.526387613106741E+28$$