সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=325$$ এবং সাধারণ অনুপাত: $$r=0.015384615384615385$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=325$$

$$a_2=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{2-1}=325\cdot {0.015384615384615385}^1=325\cdot 0.015384615384615385=5$$

$$a_3=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{3-1}=325\cdot {0.015384615384615385}^2=325\cdot 0.0002366863905325444=0.07692307692307693$$

$$a_4=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{4-1}=325\cdot {0.015384615384615385}^3=325\cdot 3.6413290851160678E-06=0.0011834319526627221$$

$$a_5=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{5-1}=325\cdot {0.015384615384615385}^4=325\cdot 5.6020447463324125E-08=1.820664542558034E-05$$

$$a_6=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{6-1}=325\cdot {0.015384615384615385}^5=325\cdot 8.618530378972942E-10=2.8010223731662064E-07$$

$$a_7=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{7-1}=325\cdot {0.015384615384615385}^6=325\cdot 1.3259277506112221E-11=4.309265189486472E-09$$

$$a_8=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{8-1}=325\cdot {0.015384615384615385}^7=325\cdot 2.039888847094188E-13=6.629638753056111E-11$$

$$a_9=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{9-1}=325\cdot {0.015384615384615385}^8=325\cdot 3.1382905339910586E-15=1.0199444235470941E-12$$

$$a_{10}=a_1·r^{n-1}=325\cdot {0.015384615384615385}^{10-1}=325\cdot {0.015384615384615385}^9=325\cdot 4.828139283063167E-17=1.5691452669955293E-14$$