সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=323$$ এবং সাধারণ অনুপাত: $$r=0.01238390092879257$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=323$$

$$a_2=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{2-1}=323\cdot {0.01238390092879257}^1=323\cdot 0.01238390092879257=4$$

$$a_3=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{3-1}=323\cdot {0.01238390092879257}^2=323\cdot 0.0001533610022141495=0.04953560371517028$$

$$a_4=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{4-1}=323\cdot {0.01238390092879257}^3=323\cdot 1.8992074577603654E-06=0.0006134440088565981$$

$$a_5=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{5-1}=323\cdot {0.01238390092879257}^4=323\cdot 2.3519597000128364E-08=7.5968298310414616E-06$$

$$a_6=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{6-1}=323\cdot {0.01238390092879257}^5=323\cdot 2.912643591347166E-10=9.407838800051347E-08$$

$$a_7=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{7-1}=323\cdot {0.01238390092879257}^6=323\cdot 3.6069889676125897E-12=1.1650574365388665E-09$$

$$a_8=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{8-1}=323\cdot {0.01238390092879257}^7=323\cdot 4.4668594026162106E-14=1.442795587045036E-11$$

$$a_9=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{9-1}=323\cdot {0.01238390092879257}^8=323\cdot 5.531714430484472E-16=1.7867437610464842E-13$$

$$a_{10}=a_1·r^{n-1}=323\cdot {0.01238390092879257}^{10-1}=323\cdot {0.01238390092879257}^9=323\cdot 6.850420347349191E-18=2.2126857721937887E-15$$