সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=3$$ এবং সাধারণ অনুপাত: $$r=836$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=3$$

$$a_2=a_1·r^{n-1}=3\cdot {836}^{2-1}=3\cdot {836}^1=3\cdot 836=2508$$

$$a_3=a_1·r^{n-1}=3\cdot {836}^{3-1}=3\cdot {836}^2=3\cdot 698896=2096688$$

$$a_4=a_1·r^{n-1}=3\cdot {836}^{4-1}=3\cdot {836}^3=3\cdot 584277056=1752831168$$

$$a_5=a_1·r^{n-1}=3\cdot {836}^{5-1}=3\cdot {836}^4=3\cdot 488455618816=1465366856448$$

$$a_6=a_1·r^{n-1}=3\cdot {836}^{6-1}=3\cdot {836}^5=3\cdot 408348897330176=1225046691990528$$

$$a_7=a_1·r^{n-1}=3\cdot {836}^{7-1}=3\cdot {836}^6=3\cdot 3.4137967816802714E+17=1.0241390345040814E+18$$

$$a_8=a_1·r^{n-1}=3\cdot {836}^{8-1}=3\cdot {836}^7=3\cdot 2.853934109484707E+20=8.561802328454121E+20$$

$$a_9=a_1·r^{n-1}=3\cdot {836}^{9-1}=3\cdot {836}^8=3\cdot 2.385888915529215E+23=7.157666746587645E+23$$

$$a_{10}=a_1·r^{n-1}=3\cdot {836}^{10-1}=3\cdot {836}^9=3\cdot 1.9946031333824237E+26=5.983809400147271E+26$$