সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=104$$ এবং সাধারণ অনুপাত: $$r=82.46153846153847$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=104$$

$$a_2=a_1·r^{n-1}=104\cdot {82.46153846153847}^{2-1}=104\cdot {82.46153846153847}^1=104\cdot 82.46153846153847=8576$$

$$a_3=a_1·r^{n-1}=104\cdot {82.46153846153847}^{3-1}=104\cdot {82.46153846153847}^2=104\cdot 6799.905325443788=707190.1538461539$$

$$a_4=a_1·r^{n-1}=104\cdot {82.46153846153847}^{4-1}=104\cdot {82.46153846153847}^3=104\cdot 560730.6545289032=58315988.07100593$$

$$a_5=a_1·r^{n-1}=104\cdot {82.46153846153847}^{5-1}=104\cdot {82.46153846153847}^4=104\cdot 46238712.43499879=4808826093.239874$$

$$a_6=a_1·r^{n-1}=104\cdot {82.46153846153847}^{6-1}=104\cdot {82.46153846153847}^5=104\cdot 3812915363.8706694=396543197842.5496$$

$$a_7=a_1·r^{n-1}=104\cdot {82.46153846153847}^{7-1}=104\cdot {82.46153846153847}^6=104\cdot 314418866928.4122=32699562160554.867$$

$$a_8=a_1·r^{n-1}=104\cdot {82.46153846153847}^{8-1}=104\cdot {82.46153846153847}^7=104\cdot 25927463488250.6=2696456202778062.5$$

$$a_9=a_1·r^{n-1}=104\cdot {82.46153846153847}^{9-1}=104\cdot {82.46153846153847}^8=104\cdot 2138018527646511.5=2.223539268752372E+17$$

$$a_{10}=a_1·r^{n-1}=104\cdot {82.46153846153847}^{10-1}=104\cdot {82.46153846153847}^9=104\cdot 1.7630429704900464E+17=1.8335646893096483E+19$$