সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=1,004$$ এবং সাধারণ অনুপাত: $$r=0.00796812749003984$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=1004$$

$$a_2=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{2-1}=1004\cdot {0.00796812749003984}^1=1004\cdot 0.00796812749003984=8$$

$$a_3=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{3-1}=1004\cdot {0.00796812749003984}^2=1004\cdot 6.349105569752861E-05=0.06374501992031872$$

$$a_4=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{4-1}=1004\cdot {0.00796812749003984}^3=1004\cdot 5.059048262751283E-07=0.0005079284455802288$$

$$a_5=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{5-1}=1004\cdot {0.00796812749003984}^4=1004\cdot 4.03111415358668E-09=4.047238610201026E-06$$

$$a_6=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{6-1}=1004\cdot {0.00796812749003984}^5=1004\cdot 3.212043150268271E-11=3.224891322869344E-08$$

$$a_7=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{7-1}=1004\cdot {0.00796812749003984}^6=1004\cdot 2.559396932484678E-13=2.5696345202146163E-10$$

$$a_8=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{8-1}=1004\cdot {0.00796812749003984}^7=1004\cdot 2.0393601055654804E-15=2.0475175459877422E-12$$

$$a_9=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{9-1}=1004\cdot {0.00796812749003984}^8=1004\cdot 1.6249881319246856E-17=1.6314880844523843E-14$$

$$a_{10}=a_1·r^{n-1}=1004\cdot {0.00796812749003984}^{10-1}=1004\cdot {0.00796812749003984}^9=1004\cdot 1.2948112604977574E-19=1.2999905055397485E-16$$