সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=100$$ এবং সাধারণ অনুপাত: $$r=0.03$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=100$$

$$a_2=a_1·r^{n-1}=100\cdot {0.03}^{2-1}=100\cdot {0.03}^1=100\cdot 0.03=3$$

$$a_3=a_1·r^{n-1}=100\cdot {0.03}^{3-1}=100\cdot {0.03}^2=100\cdot 0.0009=0.09$$

$$a_4=a_1·r^{n-1}=100\cdot {0.03}^{4-1}=100\cdot {0.03}^3=100\cdot 2.6999999999999996E-05=0.0026999999999999997$$

$$a_5=a_1·r^{n-1}=100\cdot {0.03}^{5-1}=100\cdot {0.03}^4=100\cdot 8.099999999999999E-07=8.099999999999999E-05$$

$$a_6=a_1·r^{n-1}=100\cdot {0.03}^{6-1}=100\cdot {0.03}^5=100\cdot 2.4299999999999996E-08=2.4299999999999996E-06$$

$$a_7=a_1·r^{n-1}=100\cdot {0.03}^{7-1}=100\cdot {0.03}^6=100\cdot 7.289999999999999E-10=7.289999999999998E-08$$

$$a_8=a_1·r^{n-1}=100\cdot {0.03}^{8-1}=100\cdot {0.03}^7=100\cdot 2.1869999999999995E-11=2.1869999999999996E-09$$

$$a_9=a_1·r^{n-1}=100\cdot {0.03}^{9-1}=100\cdot {0.03}^8=100\cdot 6.560999999999998E-13=6.560999999999998E-11$$

$$a_{10}=a_1·r^{n-1}=100\cdot {0.03}^{10-1}=100\cdot {0.03}^9=100\cdot 1.9682999999999994E-14=1.9682999999999996E-12$$