সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=95$$ এবং সাধারণ অনুপাত: $$r=0.042105263157894736$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=95$$

$$a_2=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{2-1}=95\cdot {0.042105263157894736}^1=95\cdot 0.042105263157894736=4$$

$$a_3=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{3-1}=95\cdot {0.042105263157894736}^2=95\cdot 0.0017728531855955678=0.16842105263157894$$

$$a_4=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{4-1}=95\cdot {0.042105263157894736}^3=95\cdot 7.464644991981338E-05=0.007091412742382271$$

$$a_5=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{5-1}=95\cdot {0.042105263157894736}^4=95\cdot 3.1430084176763526E-06=0.0002985857996792535$$

$$a_6=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{6-1}=95\cdot {0.042105263157894736}^5=95\cdot 1.3233719653374116E-07=1.257203367070541E-05$$

$$a_7=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{7-1}=95\cdot {0.042105263157894736}^6=95\cdot 5.572092485631207E-09=5.293487861349646E-07$$

$$a_8=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{8-1}=95\cdot {0.042105263157894736}^7=95\cdot 2.3461442044762974E-10=2.2288369942524824E-08$$

$$a_9=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{9-1}=95\cdot {0.042105263157894736}^8=95\cdot 9.878501913584411E-12=9.38457681790519E-10$$

$$a_{10}=a_1·r^{n-1}=95\cdot {0.042105263157894736}^{10-1}=95\cdot {0.042105263157894736}^9=95\cdot 4.159369226772383E-13=3.951400765433764E-11$$