সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=83$$ এবং সাধারণ অনুপাত: $$r=0.04819277108433735$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=83$$

$$a_2=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{2-1}=83\cdot {0.04819277108433735}^1=83\cdot 0.04819277108433735=4$$

$$a_3=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{3-1}=83\cdot {0.04819277108433735}^2=83\cdot 0.0023225431847873424=0.1927710843373494$$

$$a_4=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{4-1}=83\cdot {0.04819277108433735}^3=83\cdot 0.00011192979203794421=0.00929017273914937$$

$$a_5=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{5-1}=83\cdot {0.04819277108433735}^4=83\cdot 5.394206845202131E-06=0.00044771916815177686$$

$$a_6=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{6-1}=83\cdot {0.04819277108433735}^5=83\cdot 2.599617756723919E-07=2.1576827380808527E-05$$

$$a_7=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{7-1}=83\cdot {0.04819277108433735}^6=83\cdot 1.252827834565744E-08=1.0398471026895676E-06$$

$$a_8=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{8-1}=83\cdot {0.04819277108433735}^7=83\cdot 6.037724503931297E-10=5.011311338262977E-08$$

$$a_9=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{9-1}=83\cdot {0.04819277108433735}^8=83\cdot 2.909746748882553E-11=2.415089801572519E-09$$

$$a_{10}=a_1·r^{n-1}=83\cdot {0.04819277108433735}^{10-1}=83\cdot {0.04819277108433735}^9=83\cdot 1.4022875898229171E-12=1.1638986995530212E-10$$