সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=76$$ এবং সাধারণ অনুপাত: $$r=1.25$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=76$$

$$a_2=a_1·r^{n-1}=76\cdot {1.25}^{2-1}=76\cdot {1.25}^1=76\cdot 1.25=95$$

$$a_3=a_1·r^{n-1}=76\cdot {1.25}^{3-1}=76\cdot {1.25}^2=76\cdot 1.5625=118.75$$

$$a_4=a_1·r^{n-1}=76\cdot {1.25}^{4-1}=76\cdot {1.25}^3=76\cdot 1.953125=148.4375$$

$$a_5=a_1·r^{n-1}=76\cdot {1.25}^{5-1}=76\cdot {1.25}^4=76\cdot 2.44140625=185.546875$$

$$a_6=a_1·r^{n-1}=76\cdot {1.25}^{6-1}=76\cdot {1.25}^5=76\cdot 3.0517578125=231.93359375$$

$$a_7=a_1·r^{n-1}=76\cdot {1.25}^{7-1}=76\cdot {1.25}^6=76\cdot 3.814697265625=289.9169921875$$

$$a_8=a_1·r^{n-1}=76\cdot {1.25}^{8-1}=76\cdot {1.25}^7=76\cdot 4.76837158203125=362.396240234375$$

$$a_9=a_1·r^{n-1}=76\cdot {1.25}^{9-1}=76\cdot {1.25}^8=76\cdot 5.9604644775390625=452.99530029296875$$

$$a_{10}=a_1·r^{n-1}=76\cdot {1.25}^{10-1}=76\cdot {1.25}^9=76\cdot 7.450580596923828=566.2441253662109$$