সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=60$$ এবং সাধারণ অনুপাত: $$r=1.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=60$$

$$a_2=a_1·r^{n-1}=60\cdot {1.6}^{2-1}=60\cdot {1.6}^1=60\cdot 1.6=96$$

$$a_3=a_1·r^{n-1}=60\cdot {1.6}^{3-1}=60\cdot {1.6}^2=60\cdot 2.5600000000000005=153.60000000000002$$

$$a_4=a_1·r^{n-1}=60\cdot {1.6}^{4-1}=60\cdot {1.6}^3=60\cdot 4.096000000000001=245.76000000000005$$

$$a_5=a_1·r^{n-1}=60\cdot {1.6}^{5-1}=60\cdot {1.6}^4=60\cdot 6.553600000000001=393.21600000000007$$

$$a_6=a_1·r^{n-1}=60\cdot {1.6}^{6-1}=60\cdot {1.6}^5=60\cdot 10.485760000000003=629.1456000000002$$

$$a_7=a_1·r^{n-1}=60\cdot {1.6}^{7-1}=60\cdot {1.6}^6=60\cdot 16.777216000000006=1006.6329600000004$$

$$a_8=a_1·r^{n-1}=60\cdot {1.6}^{8-1}=60\cdot {1.6}^7=60\cdot 26.84354560000001=1610.6127360000005$$

$$a_9=a_1·r^{n-1}=60\cdot {1.6}^{9-1}=60\cdot {1.6}^8=60\cdot 42.94967296000002=2576.9803776000012$$

$$a_{10}=a_1·r^{n-1}=60\cdot {1.6}^{10-1}=60\cdot {1.6}^9=60\cdot 68.71947673600003=4123.168604160002$$