সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=60$$ এবং সাধারণ অনুপাত: $$r=0.15$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=60$$

$$a_2=a_1·r^{n-1}=60\cdot {0.15}^{2-1}=60\cdot {0.15}^1=60\cdot 0.15=9$$

$$a_3=a_1·r^{n-1}=60\cdot {0.15}^{3-1}=60\cdot {0.15}^2=60\cdot 0.0225=1.3499999999999999$$

$$a_4=a_1·r^{n-1}=60\cdot {0.15}^{4-1}=60\cdot {0.15}^3=60\cdot 0.0033749999999999995=0.20249999999999996$$

$$a_5=a_1·r^{n-1}=60\cdot {0.15}^{5-1}=60\cdot {0.15}^4=60\cdot 0.00050625=0.030375$$

$$a_6=a_1·r^{n-1}=60\cdot {0.15}^{6-1}=60\cdot {0.15}^5=60\cdot 7.593749999999998E-05=0.004556249999999999$$

$$a_7=a_1·r^{n-1}=60\cdot {0.15}^{7-1}=60\cdot {0.15}^6=60\cdot 1.1390624999999997E-05=0.0006834374999999998$$

$$a_8=a_1·r^{n-1}=60\cdot {0.15}^{8-1}=60\cdot {0.15}^7=60\cdot 1.7085937499999996E-06=0.00010251562499999997$$

$$a_9=a_1·r^{n-1}=60\cdot {0.15}^{9-1}=60\cdot {0.15}^8=60\cdot 2.562890624999999E-07=1.5377343749999994E-05$$

$$a_{10}=a_1·r^{n-1}=60\cdot {0.15}^{10-1}=60\cdot {0.15}^9=60\cdot 3.844335937499999E-08=2.3066015624999993E-06$$