সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=60$$ এবং সাধারণ অনুপাত: $$r=1.1$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=60$$

$$a_2=a_1·r^{n-1}=60\cdot {1.1}^{2-1}=60\cdot {1.1}^1=60\cdot 1.1=66$$

$$a_3=a_1·r^{n-1}=60\cdot {1.1}^{3-1}=60\cdot {1.1}^2=60\cdot 1.2100000000000002=72.60000000000001$$

$$a_4=a_1·r^{n-1}=60\cdot {1.1}^{4-1}=60\cdot {1.1}^3=60\cdot 1.3310000000000004=79.86000000000003$$

$$a_5=a_1·r^{n-1}=60\cdot {1.1}^{5-1}=60\cdot {1.1}^4=60\cdot 1.4641000000000004=87.84600000000002$$

$$a_6=a_1·r^{n-1}=60\cdot {1.1}^{6-1}=60\cdot {1.1}^5=60\cdot 1.6105100000000006=96.63060000000003$$

$$a_7=a_1·r^{n-1}=60\cdot {1.1}^{7-1}=60\cdot {1.1}^6=60\cdot 1.7715610000000008=106.29366000000005$$

$$a_8=a_1·r^{n-1}=60\cdot {1.1}^{8-1}=60\cdot {1.1}^7=60\cdot 1.9487171000000012=116.92302600000008$$

$$a_9=a_1·r^{n-1}=60\cdot {1.1}^{9-1}=60\cdot {1.1}^8=60\cdot 2.1435888100000016=128.61532860000008$$

$$a_{10}=a_1·r^{n-1}=60\cdot {1.1}^{10-1}=60\cdot {1.1}^9=60\cdot 2.357947691000002=141.47686146000012$$