সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=60$$ এবং সাধারণ অনুপাত: $$r=2.4$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=60$$

$$a_2=a_1·r^{n-1}=60\cdot {2.4}^{2-1}=60\cdot {2.4}^1=60\cdot 2.4=144$$

$$a_3=a_1·r^{n-1}=60\cdot {2.4}^{3-1}=60\cdot {2.4}^2=60\cdot 5.76=345.59999999999997$$

$$a_4=a_1·r^{n-1}=60\cdot {2.4}^{4-1}=60\cdot {2.4}^3=60\cdot 13.823999999999998=829.4399999999998$$

$$a_5=a_1·r^{n-1}=60\cdot {2.4}^{5-1}=60\cdot {2.4}^4=60\cdot 33.1776=1990.656$$

$$a_6=a_1·r^{n-1}=60\cdot {2.4}^{6-1}=60\cdot {2.4}^5=60\cdot 79.62623999999998=4777.574399999999$$

$$a_7=a_1·r^{n-1}=60\cdot {2.4}^{7-1}=60\cdot {2.4}^6=60\cdot 191.10297599999996=11466.178559999997$$

$$a_8=a_1·r^{n-1}=60\cdot {2.4}^{8-1}=60\cdot {2.4}^7=60\cdot 458.6471423999999=27518.828543999993$$

$$a_9=a_1·r^{n-1}=60\cdot {2.4}^{9-1}=60\cdot {2.4}^8=60\cdot 1100.7531417599996=66045.18850559997$$

$$a_{10}=a_1·r^{n-1}=60\cdot {2.4}^{10-1}=60\cdot {2.4}^9=60\cdot 2641.8075402239992=158508.45241343995$$