সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=510$$ এবং সাধারণ অনুপাত: $$r=0.00392156862745098$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=510$$

$$a_2=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{2-1}=510\cdot {0.00392156862745098}^1=510\cdot 0.00392156862745098=2$$

$$a_3=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{3-1}=510\cdot {0.00392156862745098}^2=510\cdot 1.5378700499807765E-05=0.00784313725490196$$

$$a_4=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{4-1}=510\cdot {0.00392156862745098}^3=510\cdot 6.030862941101084E-08=3.075740099961553E-05$$

$$a_5=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{5-1}=510\cdot {0.00392156862745098}^4=510\cdot 2.365044290627876E-10=1.206172588220217E-07$$

$$a_6=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{6-1}=510\cdot {0.00392156862745098}^5=510\cdot 9.274683492658337E-13=4.730088581255752E-10$$

$$a_7=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{7-1}=510\cdot {0.00392156862745098}^6=510\cdot 3.637130781434642E-15=1.8549366985316675E-12$$

$$a_8=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{8-1}=510\cdot {0.00392156862745098}^7=510\cdot 1.4263257966410363E-17=7.274261562869286E-15$$

$$a_9=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{9-1}=510\cdot {0.00392156862745098}^8=510\cdot 5.593434496631515E-20=2.8526515932820727E-17$$

$$a_{10}=a_1·r^{n-1}=510\cdot {0.00392156862745098}^{10-1}=510\cdot {0.00392156862745098}^9=510\cdot 2.1935037241692214E-22=1.118686899326303E-19$$