সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=50$$ এবং সাধারণ অনুপাত: $$r=1.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=50$$

$$a_2=a_1·r^{n-1}=50\cdot {1.6}^{2-1}=50\cdot {1.6}^1=50\cdot 1.6=80$$

$$a_3=a_1·r^{n-1}=50\cdot {1.6}^{3-1}=50\cdot {1.6}^2=50\cdot 2.5600000000000005=128.00000000000003$$

$$a_4=a_1·r^{n-1}=50\cdot {1.6}^{4-1}=50\cdot {1.6}^3=50\cdot 4.096000000000001=204.80000000000004$$

$$a_5=a_1·r^{n-1}=50\cdot {1.6}^{5-1}=50\cdot {1.6}^4=50\cdot 6.553600000000001=327.68000000000006$$

$$a_6=a_1·r^{n-1}=50\cdot {1.6}^{6-1}=50\cdot {1.6}^5=50\cdot 10.485760000000003=524.2880000000001$$

$$a_7=a_1·r^{n-1}=50\cdot {1.6}^{7-1}=50\cdot {1.6}^6=50\cdot 16.777216000000006=838.8608000000003$$

$$a_8=a_1·r^{n-1}=50\cdot {1.6}^{8-1}=50\cdot {1.6}^7=50\cdot 26.84354560000001=1342.1772800000006$$

$$a_9=a_1·r^{n-1}=50\cdot {1.6}^{9-1}=50\cdot {1.6}^8=50\cdot 42.94967296000002=2147.4836480000013$$

$$a_{10}=a_1·r^{n-1}=50\cdot {1.6}^{10-1}=50\cdot {1.6}^9=50\cdot 68.71947673600003=3435.9738368000017$$