সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=435$$ এবং সাধারণ অনুপাত: $$r=0.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=435$$

$$a_2=a_1·r^{n-1}=435\cdot {0.6}^{2-1}=435\cdot {0.6}^1=435\cdot 0.6=261$$

$$a_3=a_1·r^{n-1}=435\cdot {0.6}^{3-1}=435\cdot {0.6}^2=435\cdot 0.36=156.6$$

$$a_4=a_1·r^{n-1}=435\cdot {0.6}^{4-1}=435\cdot {0.6}^3=435\cdot 0.21599999999999997=93.96$$

$$a_5=a_1·r^{n-1}=435\cdot {0.6}^{5-1}=435\cdot {0.6}^4=435\cdot 0.1296=56.376$$

$$a_6=a_1·r^{n-1}=435\cdot {0.6}^{6-1}=435\cdot {0.6}^5=435\cdot 0.07775999999999998=33.825599999999994$$

$$a_7=a_1·r^{n-1}=435\cdot {0.6}^{7-1}=435\cdot {0.6}^6=435\cdot 0.04665599999999999=20.295359999999995$$

$$a_8=a_1·r^{n-1}=435\cdot {0.6}^{8-1}=435\cdot {0.6}^7=435\cdot 0.027993599999999993=12.177215999999998$$

$$a_9=a_1·r^{n-1}=435\cdot {0.6}^{9-1}=435\cdot {0.6}^8=435\cdot 0.016796159999999994=7.306329599999997$$

$$a_{10}=a_1·r^{n-1}=435\cdot {0.6}^{10-1}=435\cdot {0.6}^9=435\cdot 0.010077695999999997=4.383797759999998$$