সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=4,175$$ এবং সাধারণ অনুপাত: $$r=0.005988023952095809$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=4175$$

$$a_2=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{2-1}=4175\cdot {0.005988023952095809}^1=4175\cdot 0.005988023952095809=25$$

$$a_3=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{3-1}=4175\cdot {0.005988023952095809}^2=4175\cdot 3.585643085087311E-05=0.14970059880239522$$

$$a_4=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{4-1}=4175\cdot {0.005988023952095809}^3=4175\cdot 2.1470916677169528E-07=0.0008964107712718278$$

$$a_5=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{5-1}=4175\cdot {0.005988023952095809}^4=4175\cdot 1.2856836333634449E-09=5.367729169292383E-06$$

$$a_6=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{6-1}=4175\cdot {0.005988023952095809}^5=4175\cdot 7.698704391397874E-12=3.214209083408613E-08$$

$$a_7=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{7-1}=4175\cdot {0.005988023952095809}^6=4175\cdot 4.6100026295795654E-14=1.9246760978494686E-10$$

$$a_8=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{8-1}=4175\cdot {0.005988023952095809}^7=4175\cdot 2.76048061651471E-16=1.1525006573948914E-12$$

$$a_9=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{9-1}=4175\cdot {0.005988023952095809}^8=4175\cdot 1.6529824050986288E-18=6.901201541286775E-15$$

$$a_{10}=a_1·r^{n-1}=4175\cdot {0.005988023952095809}^{10-1}=4175\cdot {0.005988023952095809}^9=4175\cdot 9.898098234123526E-21=4.132456012746572E-17$$