সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=369$$ এবং সাধারণ অনুপাত: $$r=0.01084010840108401$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=369$$

$$a_2=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{2-1}=369\cdot {0.01084010840108401}^1=369\cdot 0.01084010840108401=4$$

$$a_3=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{3-1}=369\cdot {0.01084010840108401}^2=369\cdot 0.00011750795014725215=0.04336043360433604$$

$$a_4=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{4-1}=369\cdot {0.01084010840108401}^3=369\cdot 1.273798917585389E-06=0.0004700318005890086$$

$$a_5=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{5-1}=369\cdot {0.01084010840108401}^4=369\cdot 1.3808118347809097E-08=5.095195670341557E-06$$

$$a_6=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{6-1}=369\cdot {0.01084010840108401}^5=369\cdot 1.4968149970524766E-10=5.523247339123639E-08$$

$$a_7=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{7-1}=369\cdot {0.01084010840108401}^6=369\cdot 1.622563682441709E-12=5.987259988209907E-10$$

$$a_8=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{8-1}=369\cdot {0.01084010840108401}^7=369\cdot 1.758876620533018E-14=6.490254729766837E-12$$

$$a_9=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{9-1}=369\cdot {0.01084010840108401}^8=369\cdot 1.906641323071022E-16=7.035506482132071E-14$$

$$a_{10}=a_1·r^{n-1}=369\cdot {0.01084010840108401}^{10-1}=369\cdot {0.01084010840108401}^9=369\cdot 2.066819862407612E-18=7.626565292284088E-16$$