সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=360$$ এবং সাধারণ অনুপাত: $$r=1.2$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=360$$

$$a_2=a_1·r^{n-1}=360\cdot {1.2}^{2-1}=360\cdot {1.2}^1=360\cdot 1.2=432$$

$$a_3=a_1·r^{n-1}=360\cdot {1.2}^{3-1}=360\cdot {1.2}^2=360\cdot 1.44=518.4$$

$$a_4=a_1·r^{n-1}=360\cdot {1.2}^{4-1}=360\cdot {1.2}^3=360\cdot 1.7279999999999998=622.0799999999999$$

$$a_5=a_1·r^{n-1}=360\cdot {1.2}^{5-1}=360\cdot {1.2}^4=360\cdot 2.0736=746.496$$

$$a_6=a_1·r^{n-1}=360\cdot {1.2}^{6-1}=360\cdot {1.2}^5=360\cdot 2.4883199999999994=895.7951999999998$$

$$a_7=a_1·r^{n-1}=360\cdot {1.2}^{7-1}=360\cdot {1.2}^6=360\cdot 2.9859839999999993=1074.9542399999998$$

$$a_8=a_1·r^{n-1}=360\cdot {1.2}^{8-1}=360\cdot {1.2}^7=360\cdot 3.583180799999999=1289.9450879999997$$

$$a_9=a_1·r^{n-1}=360\cdot {1.2}^{9-1}=360\cdot {1.2}^8=360\cdot 4.2998169599999985=1547.9341055999994$$

$$a_{10}=a_1·r^{n-1}=360\cdot {1.2}^{10-1}=360\cdot {1.2}^9=360\cdot 5.1597803519999985=1857.5209267199994$$