সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=35$$ এবং সাধারণ অনুপাত: $$r=2.2$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=35$$

$$a_2=a_1·r^{n-1}=35\cdot {2.2}^{2-1}=35\cdot {2.2}^1=35\cdot 2.2=77$$

$$a_3=a_1·r^{n-1}=35\cdot {2.2}^{3-1}=35\cdot {2.2}^2=35\cdot 4.840000000000001=169.40000000000003$$

$$a_4=a_1·r^{n-1}=35\cdot {2.2}^{4-1}=35\cdot {2.2}^3=35\cdot 10.648000000000003=372.6800000000001$$

$$a_5=a_1·r^{n-1}=35\cdot {2.2}^{5-1}=35\cdot {2.2}^4=35\cdot 23.425600000000006=819.8960000000002$$

$$a_6=a_1·r^{n-1}=35\cdot {2.2}^{6-1}=35\cdot {2.2}^5=35\cdot 51.53632000000002=1803.7712000000006$$

$$a_7=a_1·r^{n-1}=35\cdot {2.2}^{7-1}=35\cdot {2.2}^6=35\cdot 113.37990400000005=3968.296640000002$$

$$a_8=a_1·r^{n-1}=35\cdot {2.2}^{8-1}=35\cdot {2.2}^7=35\cdot 249.43578880000015=8730.252608000006$$

$$a_9=a_1·r^{n-1}=35\cdot {2.2}^{9-1}=35\cdot {2.2}^8=35\cdot 548.7587353600004=19206.555737600014$$

$$a_{10}=a_1·r^{n-1}=35\cdot {2.2}^{10-1}=35\cdot {2.2}^9=35\cdot 1207.269217792001=42254.422622720034$$