সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=35$$ এবং সাধারণ অনুপাত: $$r=1.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=35$$

$$a_2=a_1·r^{n-1}=35\cdot {1.6}^{2-1}=35\cdot {1.6}^1=35\cdot 1.6=56$$

$$a_3=a_1·r^{n-1}=35\cdot {1.6}^{3-1}=35\cdot {1.6}^2=35\cdot 2.5600000000000005=89.60000000000002$$

$$a_4=a_1·r^{n-1}=35\cdot {1.6}^{4-1}=35\cdot {1.6}^3=35\cdot 4.096000000000001=143.36000000000004$$

$$a_5=a_1·r^{n-1}=35\cdot {1.6}^{5-1}=35\cdot {1.6}^4=35\cdot 6.553600000000001=229.37600000000003$$

$$a_6=a_1·r^{n-1}=35\cdot {1.6}^{6-1}=35\cdot {1.6}^5=35\cdot 10.485760000000003=367.0016000000001$$

$$a_7=a_1·r^{n-1}=35\cdot {1.6}^{7-1}=35\cdot {1.6}^6=35\cdot 16.777216000000006=587.2025600000002$$

$$a_8=a_1·r^{n-1}=35\cdot {1.6}^{8-1}=35\cdot {1.6}^7=35\cdot 26.84354560000001=939.5240960000003$$

$$a_9=a_1·r^{n-1}=35\cdot {1.6}^{9-1}=35\cdot {1.6}^8=35\cdot 42.94967296000002=1503.2385536000008$$

$$a_{10}=a_1·r^{n-1}=35\cdot {1.6}^{10-1}=35\cdot {1.6}^9=35\cdot 68.71947673600003=2405.181685760001$$