সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=35$$ এবং সাধারণ অনুপাত: $$r=1.2$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=35$$

$$a_2=a_1·r^{n-1}=35\cdot {1.2}^{2-1}=35\cdot {1.2}^1=35\cdot 1.2=42$$

$$a_3=a_1·r^{n-1}=35\cdot {1.2}^{3-1}=35\cdot {1.2}^2=35\cdot 1.44=50.4$$

$$a_4=a_1·r^{n-1}=35\cdot {1.2}^{4-1}=35\cdot {1.2}^3=35\cdot 1.7279999999999998=60.47999999999999$$

$$a_5=a_1·r^{n-1}=35\cdot {1.2}^{5-1}=35\cdot {1.2}^4=35\cdot 2.0736=72.576$$

$$a_6=a_1·r^{n-1}=35\cdot {1.2}^{6-1}=35\cdot {1.2}^5=35\cdot 2.4883199999999994=87.09119999999999$$

$$a_7=a_1·r^{n-1}=35\cdot {1.2}^{7-1}=35\cdot {1.2}^6=35\cdot 2.9859839999999993=104.50943999999997$$

$$a_8=a_1·r^{n-1}=35\cdot {1.2}^{8-1}=35\cdot {1.2}^7=35\cdot 3.583180799999999=125.41132799999997$$

$$a_9=a_1·r^{n-1}=35\cdot {1.2}^{9-1}=35\cdot {1.2}^8=35\cdot 4.2998169599999985=150.49359359999994$$

$$a_{10}=a_1·r^{n-1}=35\cdot {1.2}^{10-1}=35\cdot {1.2}^9=35\cdot 5.1597803519999985=180.59231231999996$$