সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=32$$ এবং সাধারণ অনুপাত: $$r=0.90625$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=32$$

$$a_2=a_1·r^{n-1}=32\cdot {0.90625}^{2-1}=32\cdot {0.90625}^1=32\cdot 0.90625=29$$

$$a_3=a_1·r^{n-1}=32\cdot {0.90625}^{3-1}=32\cdot {0.90625}^2=32\cdot 0.8212890625=26.28125$$

$$a_4=a_1·r^{n-1}=32\cdot {0.90625}^{4-1}=32\cdot {0.90625}^3=32\cdot 0.744293212890625=23.8173828125$$

$$a_5=a_1·r^{n-1}=32\cdot {0.90625}^{5-1}=32\cdot {0.90625}^4=32\cdot 0.6745157241821289=21.584503173828125$$

$$a_6=a_1·r^{n-1}=32\cdot {0.90625}^{6-1}=32\cdot {0.90625}^5=32\cdot 0.6112798750400543=19.56095600128174$$

$$a_7=a_1·r^{n-1}=32\cdot {0.90625}^{7-1}=32\cdot {0.90625}^6=32\cdot 0.5539723867550492=17.727116376161575$$

$$a_8=a_1·r^{n-1}=32\cdot {0.90625}^{8-1}=32\cdot {0.90625}^7=32\cdot 0.5020374754967634=16.065199215896428$$

$$a_9=a_1·r^{n-1}=32\cdot {0.90625}^{9-1}=32\cdot {0.90625}^8=32\cdot 0.4549714621689418=14.559086789406138$$

$$a_{10}=a_1·r^{n-1}=32\cdot {0.90625}^{10-1}=32\cdot {0.90625}^9=32\cdot 0.4123178875906035=13.194172402899312$$