সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=32$$ এবং সাধারণ অনুপাত: $$r=3.90625$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=32$$

$$a_2=a_1·r^{n-1}=32\cdot {3.90625}^{2-1}=32\cdot {3.90625}^1=32\cdot 3.90625=125$$

$$a_3=a_1·r^{n-1}=32\cdot {3.90625}^{3-1}=32\cdot {3.90625}^2=32\cdot 15.2587890625=488.28125$$

$$a_4=a_1·r^{n-1}=32\cdot {3.90625}^{4-1}=32\cdot {3.90625}^3=32\cdot 59.604644775390625=1907.3486328125$$

$$a_5=a_1·r^{n-1}=32\cdot {3.90625}^{5-1}=32\cdot {3.90625}^4=32\cdot 232.83064365386963=7450.580596923828$$

$$a_6=a_1·r^{n-1}=32\cdot {3.90625}^{6-1}=32\cdot {3.90625}^5=32\cdot 909.4947017729282=29103.830456733704$$

$$a_7=a_1·r^{n-1}=32\cdot {3.90625}^{7-1}=32\cdot {3.90625}^6=32\cdot 3552.713678800501=113686.83772161603$$

$$a_8=a_1·r^{n-1}=32\cdot {3.90625}^{8-1}=32\cdot {3.90625}^7=32\cdot 13877.787807814457=444089.2098500626$$

$$a_9=a_1·r^{n-1}=32\cdot {3.90625}^{9-1}=32\cdot {3.90625}^8=32\cdot 54210.10862427522=1734723.475976807$$

$$a_{10}=a_1·r^{n-1}=32\cdot {3.90625}^{10-1}=32\cdot {3.90625}^9=32\cdot 211758.2368135751=6776263.578034403$$