সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=1,949$$ এবং সাধারণ অনুপাত: $$r=0.9774243201641868$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=1949$$

$$a_2=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{2-1}=1949\cdot {0.9774243201641868}^1=1949\cdot 0.9774243201641868=1905$$

$$a_3=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{3-1}=1949\cdot {0.9774243201641868}^2=1949\cdot 0.9553583016484227=1861.9933299127758$$

$$a_4=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{4-1}=1949\cdot {0.9774243201641868}^3=1949\cdot 0.9337904385019217=1819.9575646402454$$

$$a_5=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{5-1}=1949\cdot {0.9774243201641868}^4=1949\cdot 0.9127094845285587=1778.870785346161$$

$$a_6=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{6-1}=1949\cdot {0.9774243201641868}^5=1949\cdot 0.8921044474227318=1738.7115680269042$$

$$a_7=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{7-1}=1949\cdot {0.9774243201641868}^6=1949\cdot 0.8719645830376112=1699.4589723403042$$

$$a_8=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{8-1}=1949\cdot {0.9774243201641868}^7=1949\cdot 0.8522793897827857=1661.0925306866493$$

$$a_9=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{9-1}=1949\cdot {0.9774243201641868}^8=1949\cdot 0.8330386031483873=1623.5922375362068$$

$$a_{10}=a_1·r^{n-1}=1949\cdot {0.9774243201641868}^{10-1}=1949\cdot {0.9774243201641868}^9=1949\cdot 0.8142321903528362=1586.9385389976778$$