সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=1,625$$ এবং সাধারণ অনুপাত: $$r=0.024615384615384615$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=1625$$

$$a_2=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{2-1}=1625\cdot {0.024615384615384615}^1=1625\cdot 0.024615384615384615=40$$

$$a_3=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{3-1}=1625\cdot {0.024615384615384615}^2=1625\cdot 0.0006059171597633136=0.9846153846153846$$

$$a_4=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{4-1}=1625\cdot {0.024615384615384615}^3=1625\cdot 1.4914883932635412E-05=0.024236686390532544$$

$$a_5=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{5-1}=1625\cdot {0.024615384615384615}^4=1625\cdot 3.671356044956409E-07=0.0005965953573054165$$

$$a_6=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{6-1}=1625\cdot {0.024615384615384615}^5=1625\cdot 9.03718411066193E-09=1.4685424179825638E-05$$

$$a_7=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{7-1}=1625\cdot {0.024615384615384615}^6=1625\cdot 2.2245376272398596E-10=3.614873644264772E-07$$

$$a_8=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{8-1}=1625\cdot {0.024615384615384615}^7=1625\cdot 5.475784928590424E-12=8.89815050895944E-09$$

$$a_9=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{9-1}=1625\cdot {0.024615384615384615}^8=1625\cdot 1.3478855208837967E-13=2.1903139714361695E-10$$

$$a_{10}=a_1·r^{n-1}=1625\cdot {0.024615384615384615}^{10-1}=1625\cdot {0.024615384615384615}^9=1625\cdot 3.317872051406269E-15=5.391542083535187E-12$$