সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=15$$ এবং সাধারণ অনুপাত: $$r=1.6$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=15$$

$$a_2=a_1·r^{n-1}=15\cdot {1.6}^{2-1}=15\cdot {1.6}^1=15\cdot 1.6=24$$

$$a_3=a_1·r^{n-1}=15\cdot {1.6}^{3-1}=15\cdot {1.6}^2=15\cdot 2.5600000000000005=38.400000000000006$$

$$a_4=a_1·r^{n-1}=15\cdot {1.6}^{4-1}=15\cdot {1.6}^3=15\cdot 4.096000000000001=61.44000000000001$$

$$a_5=a_1·r^{n-1}=15\cdot {1.6}^{5-1}=15\cdot {1.6}^4=15\cdot 6.553600000000001=98.30400000000002$$

$$a_6=a_1·r^{n-1}=15\cdot {1.6}^{6-1}=15\cdot {1.6}^5=15\cdot 10.485760000000003=157.28640000000004$$

$$a_7=a_1·r^{n-1}=15\cdot {1.6}^{7-1}=15\cdot {1.6}^6=15\cdot 16.777216000000006=251.6582400000001$$

$$a_8=a_1·r^{n-1}=15\cdot {1.6}^{8-1}=15\cdot {1.6}^7=15\cdot 26.84354560000001=402.6531840000001$$

$$a_9=a_1·r^{n-1}=15\cdot {1.6}^{9-1}=15\cdot {1.6}^8=15\cdot 42.94967296000002=644.2450944000003$$

$$a_{10}=a_1·r^{n-1}=15\cdot {1.6}^{10-1}=15\cdot {1.6}^9=15\cdot 68.71947673600003=1030.7921510400006$$