সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=1,125$$ এবং সাধারণ অনুপাত: $$r=0.88$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=1125$$

$$a_2=a_1·r^{n-1}=1125\cdot {0.88}^{2-1}=1125\cdot {0.88}^1=1125\cdot 0.88=990$$

$$a_3=a_1·r^{n-1}=1125\cdot {0.88}^{3-1}=1125\cdot {0.88}^2=1125\cdot 0.7744=871.1999999999999$$

$$a_4=a_1·r^{n-1}=1125\cdot {0.88}^{4-1}=1125\cdot {0.88}^3=1125\cdot 0.681472=766.656$$

$$a_5=a_1·r^{n-1}=1125\cdot {0.88}^{5-1}=1125\cdot {0.88}^4=1125\cdot 0.59969536=674.65728$$

$$a_6=a_1·r^{n-1}=1125\cdot {0.88}^{6-1}=1125\cdot {0.88}^5=1125\cdot 0.5277319168=593.6984064$$

$$a_7=a_1·r^{n-1}=1125\cdot {0.88}^{7-1}=1125\cdot {0.88}^6=1125\cdot 0.464404086784=522.4545976320001$$

$$a_8=a_1·r^{n-1}=1125\cdot {0.88}^{8-1}=1125\cdot {0.88}^7=1125\cdot 0.40867559636992=459.76004591616004$$

$$a_9=a_1·r^{n-1}=1125\cdot {0.88}^{9-1}=1125\cdot {0.88}^8=1125\cdot 0.3596345248055296=404.5888404062208$$

$$a_{10}=a_1·r^{n-1}=1125\cdot {0.88}^{10-1}=1125\cdot {0.88}^9=1125\cdot 0.31647838182886606=356.03817955747434$$