সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=112$$ এবং সাধারণ অনুপাত: $$r=0.03571428571428571$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=112$$

$$a_2=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{2-1}=112\cdot {0.03571428571428571}^1=112\cdot 0.03571428571428571=4$$

$$a_3=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{3-1}=112\cdot {0.03571428571428571}^2=112\cdot 0.0012755102040816326=0.14285714285714285$$

$$a_4=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{4-1}=112\cdot {0.03571428571428571}^3=112\cdot 4.55539358600583E-05=0.005102040816326529$$

$$a_5=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{5-1}=112\cdot {0.03571428571428571}^4=112\cdot 1.6269262807163678E-06=0.0001822157434402332$$

$$a_6=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{6-1}=112\cdot {0.03571428571428571}^5=112\cdot 5.810451002558456E-08=6.507705122865471E-06$$

$$a_7=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{7-1}=112\cdot {0.03571428571428571}^6=112\cdot 2.0751610723423055E-09=2.3241804010233823E-07$$

$$a_8=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{8-1}=112\cdot {0.03571428571428571}^7=112\cdot 7.411289544079663E-11=8.300644289369222E-09$$

$$a_9=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{9-1}=112\cdot {0.03571428571428571}^8=112\cdot 2.6468891228855936E-12=2.964515817631865E-10$$

$$a_{10}=a_1·r^{n-1}=112\cdot {0.03571428571428571}^{10-1}=112\cdot {0.03571428571428571}^9=112\cdot 9.453175438877119E-14=1.0587556491542373E-11$$