সমাধান - জ্যামিতিক ধারা

সিরিজের সাধারণ রূপ খুঁজে পেতে, প্রথম পদ: $$a=10$$ এবং সাধারণ অনুপাত: $$r=1.8$$ জ্যামিতিক সিরিজের সূত্রে প্লাগ করুন:

$$a_1=10$$

$$a_2=a_1·r^{n-1}=10\cdot {1.8}^{2-1}=10\cdot {1.8}^1=10\cdot 1.8=18$$

$$a_3=a_1·r^{n-1}=10\cdot {1.8}^{3-1}=10\cdot {1.8}^2=10\cdot 3.24=32.400000000000006$$

$$a_4=a_1·r^{n-1}=10\cdot {1.8}^{4-1}=10\cdot {1.8}^3=10\cdot 5.832000000000001=58.32000000000001$$

$$a_5=a_1·r^{n-1}=10\cdot {1.8}^{5-1}=10\cdot {1.8}^4=10\cdot 10.4976=104.976$$

$$a_6=a_1·r^{n-1}=10\cdot {1.8}^{6-1}=10\cdot {1.8}^5=10\cdot 18.895680000000002=188.95680000000002$$

$$a_7=a_1·r^{n-1}=10\cdot {1.8}^{7-1}=10\cdot {1.8}^6=10\cdot 34.012224=340.12224000000003$$

$$a_8=a_1·r^{n-1}=10\cdot {1.8}^{8-1}=10\cdot {1.8}^7=10\cdot 61.22200320000001=612.2200320000001$$

$$a_9=a_1·r^{n-1}=10\cdot {1.8}^{9-1}=10\cdot {1.8}^8=10\cdot 110.19960576000003=1101.9960576000003$$

$$a_{10}=a_1·r^{n-1}=10\cdot {1.8}^{10-1}=10\cdot {1.8}^9=10\cdot 198.35929036800005=1983.5929036800005$$